-6p^2-2p+3=0

Solution for -6p^2-2p+3=0 equation:

-6p^2-2p+3=0

a = -6; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·(-6)·3
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{19}}{2*-6}=\frac{2-2\sqrt{19}}{-12}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{19}}{2*-6}=\frac{2+2\sqrt{19}}{-12}
$